The number of compounds which react with Hins | vedclass

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(D) Hinsberg's reagent $(C_6H_5SO_2Cl)$ reacts with primary $(1^{\circ})$ and secondary $(2^{\circ})$ amines to form sulfonamides. Tertiary $(3^{\circ

Vedclass · Accepted Answer

$5$

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(D) Hinsberg's reagent $(C_6H_5SO_2Cl)$ reacts with primary $(1^{\circ})$ and secondary $(2^{\circ})$ amines to form sulfonamides. Tertiary $(3^{\circ})$ amines do not react with it.Let us analyze the given compounds:$1$. Benzenediazonium chloride: Does not react.$2$. Dibenzamide: Does not react (amide).$3$. Aniline ($1^{\circ}$ amine): Reacts.$4$. $N$-phenylpiperidine ($3^{\circ}$ amine): Does not react.$5$. $N$-methylbenzylamine ($2^{\circ}$ amine): Reacts.$6$. $N,N$-dimethylaniline ($3^{\circ}$ amine): Does not react.$7$. Ethylenediamine ($1^{\circ}$ amine): Reacts.$8$. Piperidine ($2^{\circ}$ amine): Reacts.$9$. Pyridine ($3^{\circ}$ amine): Does not react.$10$. Propylamine ($1^{\circ}$ amine): Reacts.$11$. Urea: Does not react.The compounds that react are: Aniline,$N$-methylbenzylamine,Ethylenediamine,Piperidine,and Propylamine.Total count = $5$.

The number of compounds which react with Hinsberg's reagent (benzenesulfonyl chloride) is $ . . . . . . $.

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