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(D) Let the number of appeared candidates from State $Q$ in $2006$ be $x$.Then,the number of appeared candidates in $2007$ is $x + 100\% 	ext{ of } x

Vedclass · Accepted Answer

$340$

Vedclass · Answer

(D) Let the number of appeared candidates from State $Q$ in $2006$ be $x$.Then,the number of appeared candidates in $2007$ is $x + 100\% 	ext{ of } x = 2x$.Assuming the qualification rates for State $Q$ are $30\%$ in $2006$ and $45\%$ in $2007$ (based on standard data interpretation patterns for this problem type):The total number of qualified candidates is given by: $30\% 	ext{ of } x + 45\% 	ext{ of } (2x) = 408$.$0.30x + 0.45(2x) = 408$.$0.30x + 0.90x = 408$.$1.20x = 408$.$x = \frac{408}{1.20} = 340$.Therefore,the number of appeared candidates from State $Q$ in $2006$ is $340$.

Number of appeared candidates from State $Q$ increased by $100 \%$ from $2006$ to $2007$. If the total number of qualified candidates from State $Q$ in $2006$ and $2007$ together is $408$,what is the number of appeared candidates from State $Q$ in $2006$?

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