Number of pi electrons in cyclobutadienyl ani | vedclass

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Question

(D) The cyclobutadienyl anion $({C_4}{H_4})^{2-}$ consists of a four-membered ring with two double bonds and two negative charges on the carbons.Each

Vedclass · Accepted Answer

$8$

Vedclass · Answer

(D) The cyclobutadienyl anion $({C_4}{H_4})^{2-}$ consists of a four-membered ring with two double bonds and two negative charges on the carbons.Each double bond contributes $2$ $\pi$ electrons,totaling $4$ $\pi$ electrons.The two negative charges each represent a lone pair of electrons in a $p$-orbital,which also participate in the $\pi$ system.Therefore,total $\pi$ electrons $= 4 	ext{ (from double bonds)} + 2 	imes 2 	ext{ (from negative charges)} = 8$ $\pi$ electrons.Thus,the correct option is $D$.

Number of $\pi$ electrons in cyclobutadienyl anion $({C_4}{H_4})^{2-}$ is

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