Number of $sp$ hybridised carbon atoms in the given compound $CH_2=CH-C\equiv C-CH_2-CN$ is:

  • A
    $1$
  • B
    $2$
  • C
    $3$
  • D
    $4$

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Similar Questions

Match the following lists:
List-$I$List-$II$
$A$. Ethane$1$. $2 \ sp$ carbons
$B$. Ethylene$2$. $6 \ sp^2$ carbons
$C$. Acetylene$3$. $2 \ sp^3$ carbons
$D$. Benzene$4$. $2 \ sp^2$ carbons
$5$. $1 \ sp$ and $1 \ sp^2$ carbons

What is the hybridization shown by $C_1$ and $C_2$ carbons,respectively in the given compound? $OHC-CH=CH-CH_2-COOCH_3$

The hybridisation of the negatively charged carbon atoms in $(1)$ and $(2)$ are:
$(1)$ $CH_3^-$
$(2)$ $H_2C^- - CHO - CH_3$

In the molecule $CH \equiv C - CH = CH_2$,the hybridisation of the $C - C$ single bond is:

Which among the following possesses a $sp$ carbon in its structure?

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