My watch gains 5 seconds in 3 minutes. It was | vedclass

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(C) The watch gains $5$ seconds in $3$ minutes. This means in $3$ minutes of true time,the watch shows $3$ minutes and $5$ seconds,which is $3 + \frac

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$4$ pm

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(C) The watch gains $5$ seconds in $3$ minutes. This means in $3$ minutes of true time,the watch shows $3$ minutes and $5$ seconds,which is $3 + \frac{5}{60} = 3 + \frac{1}{12} = \frac{37}{12}$ minutes.From $7$ am to $4:15$ pm,the total time elapsed on the watch is $9$ hours and $15$ minutes,which is $540 + 15 = 555$ minutes.Since $\frac{37}{12}$ minutes of this watch correspond to $3$ minutes of true time,then $555$ minutes of this watch correspond to $\left( \frac{3}{37/12} 	imes 555 ight) = \left( \frac{36}{37} 	imes 555 ight) = 36 	imes 15 = 540$ minutes of true time.$540$ minutes is equal to $9$ hours.Adding $9$ hours to $7$ am,the true time is $4$ pm.

My watch gains $5$ seconds in $3$ minutes. It was set right at $7$ am. In the afternoon of the same day,when the watch indicates quarter past $4$ o'clock,what is the true time?

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