Most acidic among the given compounds is:

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(D) The basicity of lanthanoid hydroxides $Ln(OH)_3$ decreases as the ionic radius of the $Ln^{3+}$ ion decreases due to lanthanoid contraction.As we

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$Er(OH)_3$

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(D) The basicity of lanthanoid hydroxides $Ln(OH)_3$ decreases as the ionic radius of the $Ln^{3+}$ ion decreases due to lanthanoid contraction.As we move from $Pr$ to $Er$ in the lanthanoid series,the ionic radius decreases $(Pr^{3+} > Sm^{3+} > Gd^{3+} > Er^{3+})$.Therefore,the basicity order is $Pr(OH)_3 > Sm(OH)_3 > Gd(OH)_3 > Er(OH)_3$.Since acidity is inversely proportional to basicity,the most acidic compound is the one with the smallest ionic radius,which is $Er(OH)_3$.

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