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The reaction $2N_2O_5 \rightleftharpoons 2N_2O_4 + O_2$ is

The order of a reaction is said to be $2$ with respect to a reactant $X$,when

The mechanism of the reaction $2NO_{(g)} + Br_{2(g)} \rightarrow 2NOBr_{(g)}$ is given by:
$1) NO_{(g)} + Br_{2(g)} \rightleftharpoons NOBr_{2(g)}$ (fast)
$2) NOBr_{2(g)} + NO_{(g)} \rightarrow 2NOBr_{(g)}$ (slow)
If the second step is the rate-determining step,what is the order of the reaction with respect to $NO_{(g)}$?

For a reaction $A + B \longrightarrow P$,the following data are provided. The rate constant for this reaction in standard units is:
Entry$[A]$ in $M$$[B]$ in $M$Initial rate $(M/s)$
$1$$0.02$$0.02$$2 \times 10^{-2}$
$2$$0.02$$0.04$$4 \times 10^{-2}$
$3$$0.04$$0.04$$8 \times 10^{-2}$

The mechanism of the reaction $A + 2B \to D$ is given by:
$2B \xrightarrow{k} B_2$ [Slow]
$B_2 + A \to D$ [Fast]
The rate law expression,order with respect to $A$,order with respect to $B$,and overall order are respectively:

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