The molecular shapes of SF_4, CF_4,and XeF_4 | vedclass

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Question

(C) $1$. $SF_4$: The central atom $S$ has $6$ valence electrons. It forms $4$ bonds with $F$ atoms and has $1$ lone pair. The geometry is see-saw.$2$.

Vedclass · Accepted Answer

different,with $1, 0$,and $2$ lone pairs of electrons respectively

Vedclass · Answer

(C) $1$. $SF_4$: The central atom $S$ has $6$ valence electrons. It forms $4$ bonds with $F$ atoms and has $1$ lone pair. The geometry is see-saw.$2$. $CF_4$: The central atom $C$ has $4$ valence electrons. It forms $4$ bonds with $F$ atoms and has $0$ lone pairs. The geometry is tetrahedral.$3$. $XeF_4$: The central atom $Xe$ has $8$ valence electrons. It forms $4$ bonds with $F$ atoms and has $2$ lone pairs. The geometry is square planar.Therefore,the shapes are different,and the number of lone pairs are $1, 0$,and $2$ respectively.

The molecular shapes of $SF_4, CF_4$,and $XeF_4$ are:

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