Methyl-tert-butyl ether on heating with HI of | vedclass

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(B) The reaction of ethers with $HI$ depends on the stability of the carbocation formed.In the case of methyl-tert-butyl ether,the protonation of the

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$CH_3OH + (CH_3)_3CI$

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(B) The reaction of ethers with $HI$ depends on the stability of the carbocation formed.In the case of methyl-tert-butyl ether,the protonation of the oxygen atom occurs first.$(CH_3)_3C-O-CH_3 + HI 	o (CH_3)_3C-O^+(H)-CH_3 + I^-$.Since the tert-butyl group can form a stable $3^{\circ}$ carbocation,the $I^-$ ion attacks the tert-butyl group via an $S_N1$ mechanism,leading to the formation of tert-butyl iodide and methanol.$(CH_3)_3C-O^+(H)-CH_3 	o (CH_3)_3C^+ + CH_3OH$.$(CH_3)_3C^+ + I^- 	o (CH_3)_3CI$.Thus,the products are $(CH_3)_3CI$ and $CH_3OH$.

Methyl-tert-butyl ether on heating with $HI$ of one molar concentration gives

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The reaction of $tert$-butyl methyl ether with one equivalent of $HI$ gives:

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