In which of the following compounds is the ma | vedclass

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(A) To find the oxidation state of the central atom:$1$. In $CrO_2Cl_2$: $x + 2(-2) + 2(-1) = 0 \implies x = +6$.$2$. In $MnO_4^-$: $x + 4(-2) = -1 \i

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$CrO_2Cl_2$ and $MnO_4^-$

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(A) To find the oxidation state of the central atom:$1$. In $CrO_2Cl_2$: $x + 2(-2) + 2(-1) = 0 \implies x = +6$.$2$. In $MnO_4^-$: $x + 4(-2) = -1 \implies x = +7$.$3$. In $MnO_2$: $x + 2(-2) = 0 \implies x = +4$.$4$. In $[Fe(CN)_6]^{3-}$: $x + 6(-1) = -3 \implies x = +3$.$5$. In $[Co(CN)_6]^{3-}$: $x + 6(-1) = -3 \implies x = +3$.$6$. In $MnO$: $x + (-2) = 0 \implies x = +2$.The maximum oxidation state is $+7$ in $MnO_4^-$,which is present in option $A$.

In which of the following compounds is the maximum oxidation state of the central atom present?

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