What is the maximum number of moles of electr | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The oxidation state of $N$ in $NO_3^-$ is $+5$. To find the number of moles of electrons taken up,we calculate the change in oxidation state for e

Vedclass · Accepted Answer

$NH_3$

Vedclass · Answer

(A) The oxidation state of $N$ in $NO_3^-$ is $+5$. To find the number of moles of electrons taken up,we calculate the change in oxidation state for each reduction product: $1$. For $NO_3^- \rightarrow NH_3$: Oxidation state of $N$ changes from $+5$ to $-3$. Electrons taken $= 5 - (-3) = 8 \ mol$. $2$. For $NO_3^- \rightarrow NH_2OH$: Oxidation state of $N$ changes from $+5$ to $-1$. Electrons taken $= 5 - (-1) = 6 \ mol$. $3$. For $NO_3^- \rightarrow NO$: Oxidation state of $N$ changes from $+5$ to $+2$. Electrons taken $= 5 - 2 = 3 \ mol$. $4$. For $NO_3^- \rightarrow NO_2$: Oxidation state of $N$ changes from $+5$ to $+4$. Electrons taken $= 5 - 4 = 1 \ mol$. The maximum number of moles of electrons taken up is $8 \ mol$ (when reduced to $NH_3$).

What is the maximum number of moles of electrons taken up by one mole of $NO_3^-$ when it is reduced to the given products?

Similar Questions

Which one of the following reactions is not feasible?

$(NH_4)_2Cr_2O_7$ (Ammonium dichromate) is used in fireworks. The green coloured powder blown in air is

Assign $A, B, C, D$ from the given type of reaction.
$Na_2[Zn(OH)_4] + 4HCl \longrightarrow ZnCl_2 + 2NaCl + 4H_2O$

$200 \ mL$ of $x \times 10^{-3} \ M$ potassium dichromate $(K_2Cr_2O_7)$ is required to oxidise $750 \ mL$ of $0.6 \ M$ Mohr's salt $(FeSO_4 \cdot (NH_4)_2SO_4 \cdot 6H_2O)$ solution in acidic medium. Here $x =$ ?

$A$ solution of $KMnO_4$ on reduction yields either a colourless solution,a brown precipitate,or a green solution depending on the $pH$ of the solution. What different stages of the reduction do these represent and how are they carried out?

Vedclass Test Series

Exam Paper Generator

Online Exam Module