Match the reactions in List-I with the featur | vedclass

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(B) $(P)$ $(-)-1$-Bromo-$2$-ethylpentane undergoes $S_N2$ reaction. Since the chiral center is at $C_2$ and the reaction occurs at $C_1$,the configura

Vedclass · Accepted Answer

$P$ $\rightarrow 2; Q$ $\rightarrow 1; R$ $\rightarrow 3; S$ $\rightarrow 5$

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(B) $(P)$ $(-)-1$-Bromo-$2$-ethylpentane undergoes $S_N2$ reaction. Since the chiral center is at $C_2$ and the reaction occurs at $C_1$,the configuration at the chiral center remains unchanged,leading to retention of configuration $(P \rightarrow 2)$.$(Q)$ $(-)-2$-Bromopentane undergoes $S_N2$ reaction at the chiral center,resulting in Walden inversion,i.e.,inversion of configuration $(Q \rightarrow 1)$.$(R)$ $(-)-3$-Bromo-$3$-methylhexane undergoes $S_N1$ reaction. The carbocation formed is planar,leading to a racemic mixture,i.e.,a mixture of enantiomers $(R \rightarrow 3)$.$(S)$ The substrate has two chiral centers. $S_N1$ reaction at the chiral center creates a new chiral center,resulting in a mixture of diastereomers $(S \rightarrow 5)$.Thus,the correct match is $P$ $\rightarrow 2, Q$ $\rightarrow 1, R$ $\rightarrow 3, S$ $\rightarrow 5$.

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