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Question

(A) For $0.007\ m^2$,the leading zeros are not significant. Thus,there is $1$ significant figure. Matches $(q)$.$(b)$ For $2.64 	imes 10^{24}\ kg$,th

Vedclass · Accepted Answer

$a-q, b-s, c-p, d-r$

Vedclass · Answer

(A) For $0.007\ m^2$,the leading zeros are not significant. Thus,there is $1$ significant figure. Matches $(q)$.$(b)$ For $2.64 	imes 10^{24}\ kg$,the power of $10$ is not significant. The digits $2, 6, 4$ are significant. Thus,there are $3$ significant figures. Matches $(s)$.$(c)$ For $0.0021\ g\ cm^{-3}$,the leading zeros are not significant. The digits $2, 1$ are significant. Thus,there are $2$ significant figures. Matches $(p)$.$(d)$ For $0.0006032\ J$,the leading zeros are not significant. The digits $6, 0, 3, 2$ are significant. Thus,there are $4$ significant figures. Matches $(r)$.Therefore,the correct matching is $a-q, b-s, c-p, d-r$.

Column-$I$	Column-$II$
$(a)$ $0.007\ m^2$	$(p)$ $2$
$(b)$ $2.64 \times 10^{24}\ kg$	$(q)$ $1$
$(c)$ $0.0021\ g\ cm^{-3}$	$(r)$ $4$
$(d)$ $0.0006032\ J$	$(s)$ $3$

List-$I$ (Number)	List-$II$ (Significant figures)
$A. 1001$	$I. 3$
$B. 010.1$	$II. 4$
$C. 100.100$	$III. 5$
$D. 0.0010010$	$IV. 6$

Match the number of significant figures in the given column:

Column-$I$ Column-$II$

$(a)$ $0.007\ m^2$ $(p)$ $2$

$(b)$ $2.64 \times 10^{24}\ kg$ $(q)$ $1$

$(c)$ $0.0021\ g\ cm^{-3}$ $(r)$ $4$

$(d)$ $0.0006032\ J$ $(s)$ $3$

Similar Questions

The addition of three masses $1.6 \,g$,$7.32 \,g$,and $4.238 \,g$,expressed to the proper number of decimal places,is ....... $g$.

Match List-$I$ with List-$II$.

List-$I$ (Number) List-$II$ (Significant figures)

$A. 1001$ $I. 3$

$B. 010.1$ $II. 4$

$C. 100.100$ $III. 5$

$D. 0.0010010$ $IV. 6$

Choose the correct answer from the options given below:

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Find the area of a rectangle with dimensions $1.23 \ cm$ and $2.345 \ cm$ in $cm^2$.

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Match the number of significant figures in the given column: Column-$I$ Column-$II$ $(a)$ $0.007\ m^2$ $(p)$ $2$ $(b)$ $2.64 \times 10^{24}\ kg$ $(q)$ $1$ $(c)$ $0.0021\ g\ cm^{-3}$ $(r)$ $4$ $(d)$ $0.0006032\ J$ $(s)$ $3$