Match the following lists:List-IList-IIA. Eth | vedclass

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(A) The hybridization of carbon atoms in the given molecules is as follows:$A$. Ethane $(CH_3-CH_3)$: Both carbons are $sp^3$ hybridized. Thus,$A-3$.$

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$A-3, B-4, C-1, D-2$

Vedclass · Answer

(A) The hybridization of carbon atoms in the given molecules is as follows:$A$. Ethane $(CH_3-CH_3)$: Both carbons are $sp^3$ hybridized. Thus,$A-3$.$B$. Ethylene $(CH_2=CH_2)$: Both carbons are $sp^2$ hybridized. Thus,$B-4$.$C$. Acetylene $(CH \equiv CH)$: Both carbons are $sp$ hybridized. Thus,$C-1$.$D$. Benzene $(C_6H_6)$: All six carbons are $sp^2$ hybridized. Thus,$D-2$.Therefore,the correct matching is $A-3, B-4, C-1, D-2$.

List-$I$	List-$II$
$A$. Ethane	$1$. $2$ $sp$ carbons
$B$. Ethylene	$2$. $6$ $sp^2$ carbons
$C$. Acetylene	$3$. $2$ $sp^3$ carbons
$D$. Benzene	$4$. $2$ $sp^2$ carbons
	$5$. $1$ $sp$ and $1$ $sp^2$ carbons

Match the following lists:
List-$I$ List-$II$
$A$. Ethane $1$. $2$ $sp$ carbons
$B$. Ethylene $2$. $6$ $sp^2$ carbons
$C$. Acetylene $3$. $2$ $sp^3$ carbons
$D$. Benzene $4$. $2$ $sp^2$ carbons
$5$. $1$ $sp$ and $1$ $sp^2$ carbons

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Match the following lists:List-$I$List-$II$$A$. Ethane$1$. $2$ $sp$ carbons$B$. Ethylene$2$. $6$ $sp^2$ carbons$C$. Acetylene$3$. $2$ $sp^3$ carbons$D$. Benzene$4$. $2$ $sp^2$ carbons$5$. $1$ $sp$ and $1$ $sp^2$ carbons