Match the following. List-I List-II | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The correct matches are as follows:$(A)$ Azeotrope: These are constant boiling mixtures that show significant deviation from Raoult's law. Thus,$(

Vedclass · Accepted Answer

$A-IV, B-II, C-III, D-I$

Vedclass · Answer

(B) The correct matches are as follows:$(A)$ Azeotrope: These are constant boiling mixtures that show significant deviation from Raoult's law. Thus,$(A-IV)$.$(B)$ Henry's law: It states that the partial pressure of a gas is proportional to its mole fraction,$p = K_H x$. Thus,$(B-II)$.$(C)$ Cryoscopic constant $(K_f)$: It is defined as the depression in freezing point per unit molality,$K_f = \Delta T_f / m$. Thus,$(C-III)$.$(D)$ Van't Hoff factor $(i)$: It is used to calculate colligative properties for electrolytes,e.g.,$\Delta T_b = i K_b m$. Thus,$(D-I)$.Therefore,the correct sequence is $(A-IV, B-II, C-III, D-I)$.

List-$I$	List-$II$
$(A)$ Azeotrope	$(I)$ $\Delta T_b = i K_b m$
$(B)$ Henry's law	$(II)$ $p = K_H x$
$(C)$ Cryoscopic constant	$(III)$ $\Delta T_f / m$
$(D)$ Van't Hoff factor	$(IV)$ Deviation from Raoult's law
	$(V)$ $\pi = CRT$

Match the following.

List-$I$ List-$II$

$(A)$ Azeotrope $(I)$ $\Delta T_b = i K_b m$

$(B)$ Henry's law $(II)$ $p = K_H x$

$(C)$ Cryoscopic constant $(III)$ $\Delta T_f / m$

$(D)$ Van't Hoff factor $(IV)$ Deviation from Raoult's law

$(V)$ $\pi = CRT$

The correct answer is

Similar Questions

Calculate the solubility (in $\text{moles/litre}$) of a saturated aqueous solution of $Ag_3PO_4$ if the vapour pressure of the solution becomes $750 \ torr$ at $373 \ K$. (Assume vapour pressure of pure water at $373 \ K$ is $760 \ torr$ and density of water is $1 \ g/mL$)

Which one of the following statements is false?

At $80\,^oC$,the vapour pressure of pure liquid $A$ is $520\, mm\,Hg$ and that of pure liquid $B$ is $1000\, mm\,Hg$. If a mixture of $A$ and $B$ boils at $80\,^oC$ and $1\, atm$ pressure,the amount of $A$ in the mixture is ........... $mol\,\%$.

$A$ solution has a $1:4$ mole ratio of pentane to hexane. The vapour pressure of the pure hydrocarbons at $20 \ ^oC$ are $440 \ mm \ Hg$ for pentane and $120 \ mm \ Hg$ for hexane. The mole fraction of pentane in the vapour phase would be

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Match the following. List-$I$ List-$II$ $(A)$ Azeotrope $(I)$ $\Delta T_b = i K_b m$ $(B)$ Henry's law $(II)$ $p = K_H x$ $(C)$ Cryoscopic constant $(III)$ $\Delta T_f / m$ $(D)$ Van't Hoff factor $(IV)$ Deviation from Raoult's law $(V)$ $\pi = CRT$ The correct answer is