Match the following columns.Column IColumn II | vedclass

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(A) $\frac{dv}{dt}$ is the definition of acceleration, which is the rate of change of velocity vector. Thus, $(A \rightarrow p)$.$(B)$ $\frac{d|v|}{dt

Vedclass · Accepted Answer

$(A \rightarrow p, B \rightarrow q, C \rightarrow r, D \rightarrow s)$

Vedclass · Answer

(A) $\frac{dv}{dt}$ is the definition of acceleration, which is the rate of change of velocity vector. Thus, $(A \rightarrow p)$.$(B)$ $\frac{d|v|}{dt}$ represents the rate of change of the magnitude of velocity, which is the tangential acceleration or the rate of change of speed. Thus, $(B \rightarrow q)$.$(C)$ $\frac{dr}{dt}$ is the definition of velocity, which is the rate of change of the position vector. Thus, $(C \rightarrow r)$.$(D)$ $\left|\frac{dr}{dt}\right|$ is the magnitude of the velocity vector, which is the speed of the particle. Thus, $(D \rightarrow s)$.

Column $I$	Column $II$
$(A)$ $\frac{dv}{dt}$	$(p)$ Acceleration
$(B)$ $\frac{d\|v\|}{dt}$	$(q)$ Magnitude of acceleration
$(C)$ $\frac{dr}{dt}$	$(r)$ Velocity
$(D)$ $\left\|\frac{dr}{dt}\right\|$	$(s)$ Magnitude of velocity

Match the following columns.
Column $I$ Column $II$
$(A)$ $\frac{dv}{dt}$ $(p)$ Acceleration
$(B)$ $\frac{d|v|}{dt}$ $(q)$ Magnitude of acceleration
$(C)$ $\frac{dr}{dt}$ $(r)$ Velocity
$(D)$ $\left|\frac{dr}{dt}\right|$ $(s)$ Magnitude of velocity

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Match the following columns.Column $I$Column $II$$(A)$ $\frac{dv}{dt}$$(p)$ Acceleration$(B)$ $\frac{d|v|}{dt}$$(q)$ Magnitude of acceleration$(C)$ $\frac{dr}{dt}$$(r)$ Velocity$(D)$ $\left|\frac{dr}{dt}\right|$$(s)$ Magnitude of velocity