Match the following Column-I to Column-II bas | vedclass

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(A) To find the oxidation state of nitrogen $(N)$:$1$. In $\underline{N}H_4 Cl$: $x + 4(+1) = +1$ (since $Cl$ is $-1$),so $x + 4 = 1$,$x = -3$ $(A-R)$

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$A-R, B-Q, C-P, D-S$

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(A) To find the oxidation state of nitrogen $(N)$:$1$. In $\underline{N}H_4 Cl$: $x + 4(+1) = +1$ (since $Cl$ is $-1$),so $x + 4 = 1$,$x = -3$ $(A-R)$.$2$. In $H\underline{N}O_3$: $1 + x + 3(-2) = 0$,so $1 + x - 6 = 0$,$x = +5$ $(B-Q)$.$3$. In $\underline{N}_2 O$: $2x + (-2) = 0$,so $2x = 2$,$x = +1$ $(C-P)$.$4$. In $\underline{N}H_2 OH$: $x + 2(+1) + (-2) + 1 = 0$,so $x + 2 - 2 + 1 = 0$,$x = -1$ $(D-S)$.Thus,the correct match is $A-R, B-Q, C-P, D-S$.

Column-$I$	Column-$II$
$A$. $\underline{N}H_4 Cl$	$P$. $+1$
$B$. $H\underline{N}O_3$	$Q$. $+5$
$C$. $\underline{N}_2 O$	$R$. $-3$
$D$. $\underline{N}H_2 OH$	$S$. $-1$

Match the following Column-$I$ to Column-$II$ based on the oxidation state of the underlined nitrogen atom:
Column-$I$ Column-$II$
$A$. $\underline{N}H_4 Cl$ $P$. $+1$
$B$. $H\underline{N}O_3$ $Q$. $+5$
$C$. $\underline{N}_2 O$ $R$. $-3$
$D$. $\underline{N}H_2 OH$ $S$. $-1$

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Match the following Column-$I$ to Column-$II$ based on the oxidation state of the underlined nitrogen atom:Column-$I$Column-$II$$A$. $\underline{N}H_4 Cl$$P$. $+1$$B$. $H\underline{N}O_3$$Q$. $+5$$C$. $\underline{N}_2 O$$R$. $-3$$D$. $\underline{N}H_2 OH$$S$. $-1$