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(D) The magnification for a spherical mirror is given by $m = -v/u$.$1$. For $m = -2$: Since $m$ is negative,the image is real. $A$ real image is alwa

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$(1-b, c), (2-b, c), (3-b, d), (4-a, d)$

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(D) The magnification for a spherical mirror is given by $m = -v/u$.$1$. For $m = -2$: Since $m$ is negative,the image is real. $A$ real image is always inverted and formed by a concave mirror. Thus,$(1-b, c)$.$2$. For $m = -1/2$: Since $m$ is negative,the image is real. $A$ real image is formed by a concave mirror. Thus,$(2-b, c)$.$3$. For $m = +2$: Since $m$ is positive,the image is virtual. $A$ virtual image with magnification greater than $1$ is formed by a concave mirror. Thus,$(3-b, d)$.$4$. For $m = +1/2$: Since $m$ is positive,the image is virtual. $A$ virtual image with magnification less than $1$ is formed by a convex mirror. Thus,$(4-a, d)$.Therefore,the correct matching is $(1-b, c), (2-b, c), (3-b, d), (4-a, d)$.

Column-$I$	Column-$II$
$1$. $m = -2$	a. Convex mirror
$2$. $m = -1/2$	b. Concave mirror
$3$. $m = +2$	c. Real image
$4$. $m = +1/2$	d. Virtual image

Match the corresponding entries of Column-$I$ with Column-$II$. [Where $m$ is the magnification produced by the mirror]
Column-$I$ Column-$II$
$1$. $m = -2$ a. Convex mirror
$2$. $m = -1/2$ b. Concave mirror
$3$. $m = +2$ c. Real image
$4$. $m = +1/2$ d. Virtual image

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Match the corresponding entries of Column-$I$ with Column-$II$. [Where $m$ is the magnification produced by the mirror]Column-$I$Column-$II$$1$. $m = -2$a. Convex mirror$2$. $m = -1/2$b. Concave mirror$3$. $m = +2$c. Real image$4$. $m = +1/2$d. Virtual image