Match the following columns:
Column-$I$ Column-$II$ $(i)$ Hydrogen peroxide $(a)$ Used as air purifier in submarines $(ii)$ Calcium sulphate hemihydrate $(b)$ Used for water softening $(iii)$ Potassium superoxide $(c)$ Antiseptic $(iv)$ Calgon $(d)$ Plaster of Paris
| Column-$I$ | Column-$II$ |
|---|---|
| $(i)$ Hydrogen peroxide | $(a)$ Used as air purifier in submarines |
| $(ii)$ Calcium sulphate hemihydrate | $(b)$ Used for water softening |
| $(iii)$ Potassium superoxide | $(c)$ Antiseptic |
| $(iv)$ Calgon | $(d)$ Plaster of Paris |
- A$i-d, ii-c, iii-a, iv-b$
- B$i-c, ii-d, iii-a, iv-b$
- C$i-c, ii-d, iii-b, iv-a$
- D$i-d, ii-c, iii-b, iv-c$
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When oxalic acid reacts with conc. $H_2SO_4$,two gases produced are of neutral and acidic in nature respectively. Potassium hydroxide absorbs one of the two gases. The product formed during this absorption and the gas which gets absorbed are respectively
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View SolutionOxalic acid reacts with concentrated $H_2SO_4$ to produce a mixture of two gases. When this mixture is passed through caustic potash,one of the gases is absorbed. Which substance is formed by the absorption of the gas in caustic potash?
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View SolutionMatch the terms in Column $-I$ with the relevant item in Column $-II$.
Column $-I$ Column $-II$ $A$. Electrolysis of water produces $1$. atomic reactor $B$. Lithium aluminium hydride is used as $2$. polar molecule $C$. Hydrogen chloride is a $3$. recombines on metal surface to generate high temperature $D$. Heavy water is used in $4$. reducing agent $E$. Atomic hydrogen $5$. hydrogen and oxygen
| Column $-I$ | Column $-II$ |
| $A$. Electrolysis of water produces | $1$. atomic reactor |
| $B$. Lithium aluminium hydride is used as | $2$. polar molecule |
| $C$. Hydrogen chloride is a | $3$. recombines on metal surface to generate high temperature |
| $D$. Heavy water is used in | $4$. reducing agent |
| $E$. Atomic hydrogen | $5$. hydrogen and oxygen |
Difficult
View SolutionIn which of the following reactions,$H_2$ is liberated?
$i$. $Al_{(s)} + HCl_{(aq)} \rightarrow$
$ii$. $Al_{(s)} + NaOH_{(aq)} \rightarrow$
$iii$. $B_2H_{6(g)} + H_2O_{(l)} \rightarrow$
$iv$. $F_{2(g)} + H_2O_{(l)} \rightarrow$
$i$. $Al_{(s)} + HCl_{(aq)} \rightarrow$
$ii$. $Al_{(s)} + NaOH_{(aq)} \rightarrow$
$iii$. $B_2H_{6(g)} + H_2O_{(l)} \rightarrow$
$iv$. $F_{2(g)} + H_2O_{(l)} \rightarrow$
Correct order of boiling point $(BP)$ is:
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