Match the column I with column II.Column I (C | vedclass

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(C) Step $1$: Analyze $(i)$. The compounds are $2-chloro-2-methylbutane$ and $2-chloro-2-methylpropane$. They differ by a $-CH_2-$ group,so they are H

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$i-P, ii-R, iii-Q, iv-S$

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(C) Step $1$: Analyze $(i)$. The compounds are $2-chloro-2-methylbutane$ and $2-chloro-2-methylpropane$. They differ by a $-CH_2-$ group,so they are Homologues $(P)$.Step $2$: Analyze $(ii)$. The compounds are $ethoxybenzene$ and $1-methoxy-2-methylbenzene$. These are Metamers $(R)$ as the alkyl group attached to the oxygen atom changes.Step $3$: Analyze $(iii)$. The compounds are $methoxybenzene$ $(ether)$ and $2-methylphenol$ $(alcohol)$. These have different functional groups,so they are Functional group isomers $(Q)$.Step $4$: Analyze $(iv)$. The compounds are $2-methylpropan-1-ol$ and $2-methylpropan-2-ol$. The position of the $-OH$ group changes,so they are Position isomers $(S)$.Therefore,the correct match is $i-P, ii-R, iii-Q, iv-S$.

Column $I$ (Compounds)	Column $II$ (Relation)
$(i)$ $CH_3-CH_2-C(CH_3)_2-Cl$ and $(CH_3)_3C-Cl$	$(P)$ Homologues
$(ii)$ $C_6H_5-O-CH_2-CH_3$ and $C_6H_5-O(CH_3)-CH_3$ (ortho-methylanisole)	$(Q)$ Functional group isomers
$(iii)$ $C_6H_5-O-CH_3$ and $2-methylphenol$	$(R)$ Metamers
$(iv)$ $CH_3-CH(CH_3)-CH_2-OH$ and $(CH_3)_3C-OH$	$(S)$ Position isomers

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