Match List-$I$ with the List-$II$.
List-$I$ (Reaction) List-$II$ (Type of redox reaction) $A$. $N_{2(g)} + O_{2(g)} \rightarrow 2 NO_{(g)}$ $I$. Decomposition $B$. $2 Pb(NO_3)_{2(s)} \rightarrow 2 PbO_{(s)} + 4 NO_{2(g)} + O_{2(g)}$ $II$. Displacement $C$. $2 Na_{(s)} + 2 H_2 O_{(l)} \rightarrow 2 NaOH_{(aq)} + H_{2(g)}$ $III$. Disproportionation $D$. $2 NO_{2(g)} + 2 OH^-_{(aq)} \rightarrow NO^-_{2(aq)} + NO^-_{3(aq)} + H_2 O_{(l)}$ $IV$. Combination
Choose the correct answer from the options given below:
| List-$I$ (Reaction) | List-$II$ (Type of redox reaction) |
| $A$. $N_{2(g)} + O_{2(g)} \rightarrow 2 NO_{(g)}$ | $I$. Decomposition |
| $B$. $2 Pb(NO_3)_{2(s)} \rightarrow 2 PbO_{(s)} + 4 NO_{2(g)} + O_{2(g)}$ | $II$. Displacement |
| $C$. $2 Na_{(s)} + 2 H_2 O_{(l)} \rightarrow 2 NaOH_{(aq)} + H_{2(g)}$ | $III$. Disproportionation |
| $D$. $2 NO_{2(g)} + 2 OH^-_{(aq)} \rightarrow NO^-_{2(aq)} + NO^-_{3(aq)} + H_2 O_{(l)}$ | $IV$. Combination |
Choose the correct answer from the options given below:
- A$A-I, B-II, C-III, D-IV$
- B$A-III, B-II, C-I, D-IV$
- C$A-II, B-III, C-IV, D-I$
- D$A-IV, B-I, C-II, D-III$
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$(a)$ $6 CO_{2(g)} + 6 H_{2}O_{(l)} \rightarrow C_{6}H_{12}O_{6(aq)} + 6 O_{2(g)}$
$(b)$ $O_{3(g)} + H_{2}O_{2(l)} \rightarrow H_{2}O_{(l)} + 2 O_{2(g)}$
Why is it more appropriate to write these reactions as:
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$(b)$ $O_{3(g)} + H_{2}O_{2(l)} \rightarrow H_{2}O_{(l)} + O_{2(g)} + O_{2(g)}$
Also,suggest a technique to investigate the path of the above $(a)$ and $(b)$ redox reactions.
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