Match List-I with List-II: List-I (Molec | vedclass

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(D) The molecular shapes are determined by $VSEPR$ theory:$1$. $BrF_5$: Central atom $Br$ has $5$ bond pairs and $1$ lone pair,resulting in a square p

Vedclass · Accepted Answer

$A-IV, B-III, C-I, D-II$

Vedclass · Answer

(D) The molecular shapes are determined by $VSEPR$ theory:$1$. $BrF_5$: Central atom $Br$ has $5$ bond pairs and $1$ lone pair,resulting in a square pyramidal shape $(A-IV)$.$2$. $H_2O$: Central atom $O$ has $2$ bond pairs and $2$ lone pairs,resulting in a bent shape $(B-III)$.$3$. $ClF_3$: Central atom $Cl$ has $3$ bond pairs and $2$ lone pairs,resulting in a $T$-shape $(C-I)$.$4$. $SF_4$: Central atom $S$ has $4$ bond pairs and $1$ lone pair,resulting in a see-saw shape $(D-II)$.Therefore,the correct matching is $A-IV, B-III, C-I, D-II$.

List-$I$ (Molecule)	List-$II$ (Shape)
$A$. $BrF_5$	$I$. $T$-shape
$B$. $H_2O$	$II$. See-saw
$C$. $ClF_3$	$III$. Bent
$D$. $SF_4$	$IV$. Square pyramidal

Match List-$I$ with List-$II$:

List-$I$ (Molecule) List-$II$ (Shape)

$A$. $BrF_5$ $I$. $T$-shape

$B$. $H_2O$ $II$. See-saw

$C$. $ClF_3$ $III$. Bent

$D$. $SF_4$ $IV$. Square pyramidal

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Match List-$I$ with List-$II$: List-$I$ (Molecule) List-$II$ (Shape) $A$. $BrF_5$ $I$. $T$-shape $B$. $H_2O$ $II$. See-saw $C$. $ClF_3$ $III$. Bent $D$. $SF_4$ $IV$. Square pyramidal

Similar Questions

Which of the following molecules has trigonal planar geometry?

Which among the following represents the correct order of variation of bond angles in the given molecules?

Which of the following is the correct decreasing order of bond angles?

The correct order of the bond angles of the compounds $SiCl_4, BF_3, BeCl_2$ and $SF_6$ is

Which of the following is the correct decreasing order of bond angles?

Vedclass Test Series

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Match List-$I$ with List-$II$:

List-$I$ (Molecule) List-$II$ (Shape)

$A$. $BrF_5$ $I$. $T$-shape

$B$. $H_2O$ $II$. See-saw

$C$. $ClF_3$ $III$. Bent

$D$. $SF_4$ $IV$. Square pyramidal