Match List -I with List -II : List -I | vedclass

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Question

(A) The correct matching is as follows:$1$. Adenine is a nitrogenous base belonging to the category of $Purines$.$2$. Anthocyanin is a secondary metab

Vedclass · Accepted Answer

$(a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)$

Vedclass · Answer

(A) The correct matching is as follows:$1$. Adenine is a nitrogenous base belonging to the category of $Purines$.$2$. Anthocyanin is a secondary metabolite that acts as a $Pigment$.$3$. Chitin is a structural $Polysaccharide$ found in the cell walls of fungi and the exoskeleton of arthropods.$4$. Codeine is a secondary metabolite classified as an $Alkaloid$.Therefore,the correct sequence is $(a) - (iv), (b) - (i), (c) - (ii), (d) - (iii)$.

List $-I$	List $-II$
$a$. Adenine	$i$. Pigment
$b$. Anthocyanin	$ii$. Polysaccharide
$c$. Chitin	$iii$. Alkaloid
$d$. Codeine	$iv$. Purine

$(1)$ Carbohydrate	$(a)$ Ester bond
$(2)$ Lipid	$(b)$ Glycosidic bond
$(3)$ Protein	$(c)$ Phosphodiester bond
$(4)$ Nucleic acid	$(d)$ Peptide bond

Match List $-I$ with List $-II$ :

List $-I$ List $-II$

$a$. Adenine $i$. Pigment

$b$. Anthocyanin $ii$. Polysaccharide

$c$. Chitin $iii$. Alkaloid

$d$. Codeine $iv$. Purine

Choose the correct answer from the options given below:

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Match List $-I$ with List $-II$ : List $-I$ List $-II$ $a$. Adenine $i$. Pigment $b$. Anthocyanin $ii$. Polysaccharide $c$. Chitin $iii$. Alkaloid $d$. Codeine $iv$. Purine Choose the correct answer from the options given below: