Masses of two substances are 1, g and 9, g re | vedclass

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(D) The relationship between kinetic energy $(K)$,momentum $(P)$,and mass $(m)$ is given by $K = \frac{P^2}{2m}$.Since the kinetic energies are the sa

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$1:3$

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(D) The relationship between kinetic energy $(K)$,momentum $(P)$,and mass $(m)$ is given by $K = \frac{P^2}{2m}$.Since the kinetic energies are the same $(K_1 = K_2)$,we have $\frac{P_1^2}{2m_1} = \frac{P_2^2}{2m_2}$.Rearranging the terms,we get $\frac{P_1^2}{P_2^2} = \frac{m_1}{m_2}$.Taking the square root on both sides,the ratio of their momenta is $\frac{P_1}{P_2} = \sqrt{\frac{m_1}{m_2}}$.Given $m_1 = 1\, g$ and $m_2 = 9\, g$,we substitute these values:$\frac{P_1}{P_2} = \sqrt{\frac{1}{9}} = \frac{1}{3}$.Therefore,the ratio of their momentum is $1:3$.

Masses of two substances are $1\, g$ and $9\, g$ respectively. If their kinetic energies are same,then the ratio of their momentum will be

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