Manganese ions (Mn^{2+}) can be oxidised by p | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) To balance the redox reaction,the number of electrons lost in the oxidation half-reaction must equal the number of electrons gained in the reducti

Vedclass · Accepted Answer

$2.5$

Vedclass · Answer

(A) To balance the redox reaction,the number of electrons lost in the oxidation half-reaction must equal the number of electrons gained in the reduction half-reaction.Reduction half-reaction: $S_2O_8^{2-} + 2e^- \longrightarrow 2SO_4^{2-}$ (Gain of $2e^-$)Oxidation half-reaction: $Mn^{2+} + 4H_2O \longrightarrow MnO_4^- + 8H^+ + 5e^-$ (Loss of $5e^-$)To equate the electrons,multiply the reduction half-reaction by $5$ and the oxidation half-reaction by $2$:$5S_2O_8^{2-} + 10e^- \longrightarrow 10SO_4^{2-}$$2Mn^{2+} + 8H_2O \longrightarrow 2MnO_4^- + 16H^+ + 10e^-$From the balanced equation,$2 \ moles$ of $Mn^{2+}$ require $5 \ moles$ of $S_2O_8^{2-}$.Therefore,$1 \ mole$ of $Mn^{2+}$ requires $5/2 = 2.5 \ moles$ of $S_2O_8^{2-}$.

Similar Questions

$2 MnO_{4}^{-} + b C_{2}O_{4}^{2-} + c H^{+} \rightarrow x Mn^{2+} + y CO_{2} + z H_{2}O$
If the above equation is balanced with integer coefficients,the value of $c$ is ...........
(Round off to the Nearest Integer).

What is the value of $n$-factor of $[Fe(CN)_6]^{-4}$ in the given reaction?
$[Fe(CN)_6]^{-4} \xrightarrow{MnO_4^-/H^{+}} Fe^{+3} + CO_2 + NO_3^-$

The reaction of sulphur in alkaline medium is given below:
$S_{8(s)} + a OH^{-}_{(aq)} \rightarrow b S^{2-}_{(aq)} + c S_{2}{O_{3}}^{2-}_{(aq)} + d H_{2}O_{(\ell)}$
The value of '$a$' is ............ (Integer answer)

Which type of reaction occurs in Kolbe's electrolysis? Why?

After balancing the equation,$C_2O_4^{2-} + H^+ + MnO_4^- \longrightarrow CO_2 + Mn^{2+} + H_2O$,the coefficient of $CO_2$ is:

Vedclass Test Series

Exam Paper Generator

Online Exam Module