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(B) The given reaction is a cross-Cannizzaro reaction between benzaldehyde $(C_6H_5CHO)$ and formaldehyde $(HCHO)$.In a cross-Cannizzaro reaction,the

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$	ext{Benzyl alcohol and Formic acid}$

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(B) The given reaction is a cross-Cannizzaro reaction between benzaldehyde $(C_6H_5CHO)$ and formaldehyde $(HCHO)$.In a cross-Cannizzaro reaction,the more reactive carbonyl compound (formaldehyde) is oxidized to the corresponding acid (formate ion,which gives formic acid $HCOOH$ upon acidification),and the less reactive carbonyl compound (benzaldehyde) is reduced to the corresponding alcohol (benzyl alcohol,$C_6H_5CH_2OH$).Therefore,the products are benzyl alcohol and formic acid.

Column-$I$ (Compound)	Column-$II$ (Attraction Forces)
$A$. Aldehyde	$i$. Intermolecular hydrogen bond formed in $ROH$ between $O^{\delta -}$ of one molecule and $H^{\delta +}$ of another molecule.
$B$. Ketone	$ii$. Dipole-dipole forces between $C^{\delta +}$ of one molecule and $O^{\delta -}$ of another molecule.
$C$. Alcohol	$iii$. van der Waals forces
$D$. Alkane	$iv$. Ionic forces

The major products of the following reaction are:

Similar Questions

The end product $(C)$ in the following sequence of reactions is:
$HC \equiv CH$ $\xrightarrow[20\% \ H_2SO_4]{1\% \ HgSO_4} A$ $\xrightarrow[H_2O]{CH_3MgX} B$ $\xrightarrow{[O]} (C)$

Which is not true about acetophenone?

Identify the products of the following reaction:
$HCHO + C_6H_5CHO \xrightarrow[ii. \ H_3O^+]{i. \ conc. \ NaOH} ?$

Identify the product of the following reaction:
$C_6H_4(CHO)_2 + \text{conc. } NaOH \xrightarrow{\text{heat}} ?$

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