What is the major product of the following E2 | vedclass

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(B) In an $E2$ elimination reaction,the base $(NaOEt)$ abstracts a $\beta$-hydrogen that is anti-periplanar to the leaving group $(Cl^-)$. For the giv

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(B) In an $E2$ elimination reaction,the base $(NaOEt)$ abstracts a $\beta$-hydrogen that is anti-periplanar to the leaving group $(Cl^-)$. For the given molecule,there are two possible $\beta$-hydrogens available for elimination. Elimination of the hydrogen at $C_2$ leads to a less substituted alkene,while elimination of the hydrogen at $C_6$ leads to a more substituted,and thus more stable,alkene. According to Zaitsev's rule,the more substituted alkene is the major product. Therefore,the product with the double bond formed towards the more substituted side is the major product.

What is the major product of the following $E2$ reaction?

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