The major product of the above reaction is:

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(A) The reaction involves the cleavage of an ether with $HI$. The ether is $3-(1-ethoxyethyl)phenol$. When $HI$ reacts with this ether,the oxygen atom

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$3-$($1$-iodoethyl)phenol + ethanol

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(A) The reaction involves the cleavage of an ether with $HI$. The ether is $3-(1-ethoxyethyl)phenol$. When $HI$ reacts with this ether,the oxygen atom of the ether is protonated by $H^+$. This forms a stable carbocation at the benzylic position (specifically,a secondary benzylic carbocation stabilized by the benzene ring). Since the carbocation is stable,the reaction proceeds via an $S_N1$ mechanism. The iodide ion $(I^-)$ attacks the carbocation to form $3-(1-iodoethyl)phenol$,and the ethyl group is released as ethanol $(C_2H_5OH)$. Thus,the major products are $3-(1-iodoethyl)phenol$ and ethanol.

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