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(A) The reaction of benzene with $n$-butyl chloride in the presence of anhydrous $AlCl_3$ is a Friedel-Crafts alkylation reaction.In this reaction,the

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sec-butylbenzene

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(A) The reaction of benzene with $n$-butyl chloride in the presence of anhydrous $AlCl_3$ is a Friedel-Crafts alkylation reaction.In this reaction,the primary carbocation formed initially $(CH_3-CH_2-CH_2-CH_2^+)$ undergoes a $1,2$-hydride shift to form a more stable secondary carbocation $(CH_3-CH_2-CH^+-CH_3)$.This secondary carbocation then attacks the benzene ring to form $sec$-butylbenzene as the major product due to the rearrangement of the alkyl group.

The major product $X$ is:

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