List-I contains aqueous solutions,and List-II | vedclass

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(A) The $pH$ values of the given substances are as follows:$1$. Vinegar is a dilute solution of acetic acid,which is acidic,so its $pH$ is approximate

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$(1-b), (2-a), (3-d), (4-c)$

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(A) The $pH$ values of the given substances are as follows:$1$. Vinegar is a dilute solution of acetic acid,which is acidic,so its $pH$ is approximately $2.5$.$2$. Human blood is slightly basic,with a $pH$ range of approximately $7.35$ to $7.45$,so it matches $pH = 7.4$.$3$. Washing soda $(Na_2CO_3)$ is a salt of a strong base and a weak acid,making its aqueous solution basic with a $pH$ of approximately $12$.$4$. Pure water is neutral,so its $pH$ is $7.0$.Therefore,the correct matching is $(1-b), (2-a), (3-d), (4-c)$.

List-$I$	List-$II$
$1.$ Vinegar solution	$a.$ $pH = 7.4$
$2.$ Blood	$b.$ $pH = 2.5$
$3.$ Washing soda solution	$c.$ $pH = 7.0$
$4.$ Pure water	$d.$ $pH = 12$

List-$I$ contains aqueous solutions,and List-$II$ contains their corresponding $pH$ values. Which of the following matches is correct?
List-$I$ List-$II$
$1.$ Vinegar solution $a.$ $pH = 7.4$
$2.$ Blood $b.$ $pH = 2.5$
$3.$ Washing soda solution $c.$ $pH = 7.0$
$4.$ Pure water $d.$ $pH = 12$

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List-$I$ contains aqueous solutions,and List-$II$ contains their corresponding $pH$ values. Which of the following matches is correct?List-$I$List-$II$$1.$ Vinegar solution$a.$ $pH = 7.4$$2.$ Blood$b.$ $pH = 2.5$$3.$ Washing soda solution$c.$ $pH = 7.0$$4.$ Pure water$d.$ $pH = 12$