Liquid rises to a height $2 \ cm$ in a capillary tube; in that case,the angle of contact between the solid and the liquid is $0^{\circ}$. The tube is lowered more now,so that the capillary is only $1 \ cm$ above the liquid. In this case,the angle of contact between the solid and liquid is $......^{\circ}$.

The heat evolved for the rise of water when one end of the capillary tube of radius $r$ is immersed vertically into water is (Assume surface tension $= T$ and density of water to be $\rho$)

The angle of contact between glass and water is $0^{\circ}$ and water rises in a glass capillary up to $6 \ cm$ (Surface tension of water is $T$). Another liquid of surface tension $2T$,angle of contact $60^{\circ}$ and relative density $2$ will rise in the same capillary up to (Given: $\cos 0^{\circ}=1, \cos 60^{\circ}=0.5$) (in $cm$)

The surface tension for pure water in a capillary tube experiment is

Two capillary tubes of same diameter are put vertically one each in two liquids whose relative densities are $0.8$ and $0.6$ and surface tensions are $60$ and $50 \text{ dyne/cm}$ respectively. The ratio of the heights of the liquids in the two tubes $\frac{h_1}{h_2}$ is:

$A$ $20\, cm$ long capillary tube is dipped in water. The water rises up to $8\, cm$. If the entire arrangement is put in a freely falling elevator,the length of water column in the capillary tube will be ...... $cm$.