Light waves from two coherent sources arrive | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The phase difference $\Delta \phi$ is related to the path difference $\Delta x$ by the formula $\Delta \phi = \frac{2 \pi}{\lambda} \cdot \Delta x

Vedclass · Accepted Answer

$\infty: 1$

Vedclass · Answer

(D) The phase difference $\Delta \phi$ is related to the path difference $\Delta x$ by the formula $\Delta \phi = \frac{2 \pi}{\lambda} \cdot \Delta x$.For the first point,$\Delta x_1 = 0$,so $\Delta \phi_1 = 0$. The intensity is $I_1 = I_{max} \cos^2(\frac{\Delta \phi_1}{2}) = I_{max} \cos^2(0) = I_{max}$.For the second point,$\Delta x_2 = \frac{\lambda}{2}$,so $\Delta \phi_2 = \frac{2 \pi}{\lambda} \cdot \frac{\lambda}{2} = \pi$. The intensity is $I_2 = I_{max} \cos^2(\frac{\pi}{2}) = 0$.The ratio of intensities is $\frac{I_1}{I_2} = \frac{I_{max}}{0} = \infty$.Thus,the ratio is $\infty: 1$.

Light waves from two coherent sources arrive at two points on a screen with path difference of $0$ and $\frac{\lambda}{2}$. The ratio of intensities at the points is $(\cos 0^{\circ}=1, \cos \pi=-1)$.

Similar Questions

Two monochromatic light beams have intensities in the ratio $1 : 9$. An interference pattern is obtained by these beams. The ratio of the intensities of maximum to minimum is (in $: 1$)

Two coherent plane waves of identical frequency,polarization,and intensity $I$ interfere at a point where they differ in phase by $60^{\circ}$. What is the resulting intensity?

In an interference experiment,the ratio of amplitudes of coherent waves is $\frac{a_1}{a_2} = \frac{1}{3}$. The ratio of maximum and minimum intensities of fringes will be

Which phenomena can be explained by the wave nature of light?

Explain the intensity at the point of superposition of waves emanating from coherent and incoherent sources.

Vedclass Test Series

Exam Paper Generator

Online Exam Module