Light passes successively through two polarim | vedclass

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(B) The rotation produced by a polarimeter tube is given by the formula $	heta = S \cdot l \cdot c$,where $S$ is the specific rotation,$l$ is the len

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(B) The rotation produced by a polarimeter tube is given by the formula $	heta = S \cdot l \cdot c$,where $S$ is the specific rotation,$l$ is the length of the tube,and $c$ is the concentration.For the first tube (dextrorotatory): $	heta_1 = S_1 \cdot l \cdot c_1 = 0.01 	imes 0.29 	imes 60 = 0.174 \ rad$.For the second tube (laevorotatory): $	heta_2 = S_2 \cdot l \cdot c_2 = 0.02 	imes 0.29 	imes 30 = 0.174 \ rad$.Since the first solution is dextrorotatory (positive rotation) and the second is laevorotatory (negative rotation),the net rotation is $	heta_{net} = 	heta_1 - 	heta_2 = 0.174 - 0.174 = 0 \ rad$.Thus,the net rotation produced is $0^\circ$.

$A$. Angle of reflection	$(i)$ $2 \sin^{-1} \left(\sqrt{\frac{2}{3}}\right)$
$B$. Angle of refraction	$(ii)$ $\sin^{-1} \left(\sqrt{\frac{2}{3}}\right) - \sin^{-1} \left(\frac{1}{\sqrt{3}}\right)$
$C$. Angle between incident and completely polarised light	$(iii)$ $\sin^{-1} \left(\frac{1}{\sqrt{3}}\right)$
$D$. Angle of deviation of the incident ray	$(iv)$ $\cos^{-1} \left(\frac{1}{\sqrt{3}}\right)$

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