Light of wavelength 4000 , mathring A is inci | vedclass

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(B) The work function $W_0$ is given by the formula $W_0 = \frac{hc}{\lambda_0}$.Using the approximation $hc \approx 12375 \, eV \cdot \mathring A$,we

Vedclass · Accepted Answer

$2.29$

Vedclass · Answer

(B) The work function $W_0$ is given by the formula $W_0 = \frac{hc}{\lambda_0}$.Using the approximation $hc \approx 12375 \, eV \cdot \mathring A$,we have:$W_0 = \frac{12375}{\lambda_0 (	ext{in } \mathring A)} \, eV$.Given the threshold wavelength $\lambda_0 = 5420 \, \mathring A$:$W_0 = \frac{12375}{5420} \approx 2.283 \, eV$.Rounding to the nearest provided option,we get $2.29 \, eV$.

Light of wavelength $4000 \, \mathring A$ is incident on a sodium surface for which the threshold wavelength of photoelectrons is $5420 \, \mathring A$. The work function of sodium is .......... $eV$.

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