Light of wavelength lambda = 5000 mathring{A | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a single slit diffraction pattern,the position of the $n^{th}$ minima is given by the formula: $x_n = \frac{n \lambda D}{d}$.Here,$n = 1$ for

Vedclass · Accepted Answer

$0.1$

Vedclass · Answer

(A) For a single slit diffraction pattern,the position of the $n^{th}$ minima is given by the formula: $x_n = \frac{n \lambda D}{d}$.Here,$n = 1$ for the first minima.Given values are: $\lambda = 5000 \ \mathring{A} = 5000 	imes 10^{-10} \ m = 5 	imes 10^{-7} \ m$,$D = 1 \ m$,and $x_1 = 5 \ mm = 5 	imes 10^{-3} \ m$.Substituting these values into the formula:$5 	imes 10^{-3} = \frac{1 	imes 5 	imes 10^{-7} 	imes 1}{d}$$d = \frac{5 	imes 10^{-7}}{5 	imes 10^{-3}} \ m$$d = 10^{-4} \ m = 0.1 \ mm$.Therefore,the width of the slit is $0.1 \ mm$.

Similar Questions

$A$ wavefront presents one,two and three $HPZ$ at points $A, B$ and $C$ respectively. If the ratio of consecutive amplitudes of $HPZ$ is $4 : 3$,then the ratio of resultant intensities at these points will be

Light appears to travel in straight lines since

$A$ single slit diffraction pattern is obtained using a beam of red light. If the red light is replaced by blue light,then:

In diffraction,all fringes have .....

How will the diffraction pattern change when yellow light is replaced by blue light? The fringes will be

Vedclass Test Series

Exam Paper Generator

Online Exam Module