Let us consider an endothermic reaction which | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For a reaction to be spontaneous,the Gibbs free energy change $\Delta G$ must be negative,where $\Delta G = \Delta H - T \Delta S$.Given that the

Vedclass · Accepted Answer

Both $\Delta H$ and $\Delta S$ are $(+ve)$

Vedclass · Answer

(A) For a reaction to be spontaneous,the Gibbs free energy change $\Delta G$ must be negative,where $\Delta G = \Delta H - T \Delta S$.Given that the reaction is endothermic,$\Delta H > 0$ (positive).At low temperature (freezing point of water,$273 \ K$),the reaction is non-spontaneous,meaning $\Delta G > 0$. This implies $\Delta H > T \Delta S$.At high temperature (boiling point of water,$373 \ K$),the reaction is spontaneous,meaning $\Delta G For $\Delta G$ to become negative as temperature $T$ increases,$\Delta S$ must be positive. Thus,both $\Delta H$ and $\Delta S$ are positive.

Let us consider an endothermic reaction which is non-spontaneous at the freezing point of water. However,the reaction is spontaneous at the boiling point of water. Choose the correct option.

Similar Questions

For the change $H_2O_{(l)} \to H_2O_{(g)}$ at $P = 1 \ atm$ and $T = 373 \ K$,the free energy change $\Delta G = 0$. This indicates that:

At what temperature $(T \ K)$ will the reaction be in equilibrium (in $K$)? $Ag_2O_{(s)} \rightarrow 2Ag_{(s)} + \frac{1}{2} O_{2(g)}$,given $\Delta H = 30.5 \ kJ \ mol^{-1}$ and $\Delta S = 0.066 \ kJ \ K^{-1} \ mol^{-1}$.

When enthalpy and entropy change for a chemical reaction are $-2.5 \times 10^3 \ cal$ and $7.4 \ cal \ K^{-1}$ respectively,predict if the reaction at $298 \ K$ is:

For a certain reaction,$\Delta H = -210 \ kJ$ and $\Delta S = -150 \ J \ K^{-1}$. Find the temperature so that $\Delta G = 0$. (in $K$)

For the reaction $x + y \rightarrow z$,the process is spontaneous at room temperature,and the reverse reaction is spontaneous at high temperature. Which of the following is true?

Vedclass Test Series

Exam Paper Generator

Online Exam Module