Let (1 - 2x + 3x^2)^{10} = a_0 + a_1x + a_2x^ | vedclass

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(D) Given the expansion $(1 - 2x + 3x^2)^{10} = a_0 + a_1x + a_2x^2 + \dots + a_{20}x^{20}$.Here,the highest power of $x$ is $n = 20$,so there are $n+

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$\frac{1024}{21}$

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(D) Given the expansion $(1 - 2x + 3x^2)^{10} = a_0 + a_1x + a_2x^2 + \dots + a_{20}x^{20}$.Here,the highest power of $x$ is $n = 20$,so there are $n+1 = 21$ terms.The sum of the coefficients is obtained by putting $x = 1$ in the expansion:$a_0 + a_1 + a_2 + \dots + a_{20} = (1 - 2(1) + 3(1)^2)^{10} = (1 - 2 + 3)^{10} = 2^{10} = 1024$.The arithmetic mean of the coefficients is given by $\frac{\sum_{i=0}^{20} a_i}{21} = \frac{1024}{21}$.

Let $(1 - 2x + 3x^2)^{10} = a_0 + a_1x + a_2x^2 + \dots + a_n x^n$,where $a_n \neq 0$. Then the arithmetic mean of $a_0, a_1, a_2, \dots, a_n$ is

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