Let $PQ$ and $RS$ be the tangents at the extremities of the diameter $PR$ of a circle of radius $r$. If $PS$ and $RQ$ intersect at a point $X$ on the circumference of the circle,then $(PQ \cdot RS)$ is equal to

  • A
    $(PX) \cdot (RX)$
  • B
    $(QX) \cdot (SX)$
  • C
    $(PX)^2 + (RX)^2$
  • D
    $(QX)^2 + (SX)^2$

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