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मान लीजिए कि $A =\left[\begin{array}{ll}0 & 1 \\ 0 & 0\end{array}\right]$ हो तो दिखाइए कि सभी $n \in N$ के लिए $(a I +b A )^{n}=a^{n} I +n a^{n-1} b A ,$ जहाँ $I$ कोटि $2$ का तत्समक आव्यूह है।
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