Let $A$ and $B$ be two independent events such that $P(B) > P(A)$. If the probability that both $A$ and $B$ happen is $\frac{1}{12}$ and the probability that neither $A$ nor $B$ happens is $\frac{1}{2}$,then:

  • A
    $P(A) = \frac{1}{6}, P(B) = \frac{1}{2}$
  • B
    $P(A) = \frac{1}{4}, P(B) = \frac{1}{3}$
  • C
    $P(A) = \frac{1}{6}, P(B) = \frac{1}{5}$
  • D
    $P(A) = \frac{1}{6}, P(B) = \frac{1}{3}$

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