(A) Given the function $f(x) = \frac{|x|}{x}$ for $x \in A$,where $A = \{x \in R, x \neq 0, -4 \leq x \leq 4\}$.If $x > 0$,then $|x| = x$,so $f(x) = \

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(A) Given the function $f(x) = \frac{|x|}{x}$ for $x \in A$,where $A = \{x \in R, x \neq 0, -4 \leq x \leq 4\}$.If $x > 0$,then $|x| = x$,so $f(x) = \frac{x}{x} = 1$.If $x Since $x$ cannot be $0$,the function only takes the values $1$ and $-1$.Therefore,the range of $f$ is $\{1, -1\}$.

Class 11 Chemistry Data Entry - Chemistry Level 0 of all question bank

Let $A = \{x \in R, x \neq 0, -4 \leq x \leq 4\}$ and $f: A \rightarrow R$ be defined by $f(x) = \frac{|x|}{x}$ for $x \in A$. Then,the range of $f$ is

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A
$\{1, -1\}$
B
$\{x: 0 \leq x \leq 1\}$
C
$1$
D
$\{x: -4 \leq x \leq 0\}$

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Let $A = \{x \in R, x \neq 0, -4 \leq x \leq 4\}$ and $f: A \rightarrow R$ be defined by $f(x) = \frac{|x|}{x}$ for $x \in A$. Then,the range of $f$ is

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In the standing wave shown,particles at the positions $A$ and $B$ have a phase difference of

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$CH_3-CH_2-CH=O$ $\xrightarrow[(2) H^{+}]{(1) \text{Tollen's reagent}} X$ $\xrightarrow[(2) \text{dry distillation}]{(1) Ca(OH)_2} Y$
$Y$ is: