Let $f: R \rightarrow R$ be defined by $f(x) = 2x + 6$,which is a bijective mapping. Then $f^{-1}(x)$ is given by:

  • A
    $ \frac{x}{2} - 3 $
  • B
    $ 2x + 6 $
  • C
    $ x - 3 $
  • D
    $ 6x + 2 $

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