Let $S = N \cup\{0\}$. Define a relation $R$ from S to $R$ by: $R =\left\{(x, y): \log _e y=x \log _e\left(\frac{2}{5}\right), x \in S, y \in R \right\}$ Then, the sum of all the elements in the range of $R$ is equal to

  • [JEE MAIN 2025]
  • A
    $\frac{5}{2}$
  • B
    $\frac{10}{9}$
  • C
    $\frac{3}{2}$
  • D
    $\frac{5}{3}$

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