Let $\hat{a}$ and $\hat{b}$ be two unit vectors such that the angle between them is $\frac{\pi}{4}$. If $\theta$ is the angle between the vectors $(\hat{a}+\hat{b})$ and $(\hat{a}+2 \hat{b}+2(\hat{a} \times \hat{b}))$,then the value of $164 \cos ^{2} \theta$ is equal to.

  • A
    $90+27 \sqrt{2}$
  • B
    $45+18 \sqrt{2}$
  • C
    $90+3 \sqrt{2}$
  • D
    $54+90 \sqrt{2}$

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