Let $OA, OB, OC$ and $OD$ be rays in the anticlockwise direction such that $\angle AOB = 100^{\circ}, \angle COD = 100^{\circ}, \angle BOC = 82^{\circ}$ and $\angle AOD = 78^{\circ}$. Is it true to say that $AOC$ and $BOD$ are lines?

(NONE) line is formed if the sum of adjacent angles around a point is $180^{\circ}$.
For $AOC$ to be a line,the sum of angles $\angle AOB + \angle BOC$ must be $180^{\circ}$.
Given $\angle AOB = 100^{\circ}$ and $\angle BOC = 82^{\circ}$,their sum is $100^{\circ} + 82^{\circ} = 182^{\circ}$.
Since $182^{\circ} \neq 180^{\circ}$,$AOC$ is not a straight line.
Similarly,for $BOD$ to be a line,the sum of angles $\angle BOC + \angle COD$ must be $180^{\circ}$.
Given $\angle BOC = 82^{\circ}$ and $\angle COD = 100^{\circ}$,their sum is $82^{\circ} + 100^{\circ} = 182^{\circ}$.
Since $182^{\circ} \neq 180^{\circ}$,$BOD$ is also not a straight line.