Let A = begin{bmatrix} 2 & 4 3 & 2 end{bmatr | vedclass

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(A) Matrix $A$ has $2$ columns,and matrix $B$ has $2$ rows. Since the number of columns in $A$ equals the number of rows in $B$,the product $AB$ is de

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$\begin{bmatrix} -6 & 26 \ -1 & 19 \end{bmatrix}$

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(A) Matrix $A$ has $2$ columns,and matrix $B$ has $2$ rows. Since the number of columns in $A$ equals the number of rows in $B$,the product $AB$ is defined.$AB = \begin{bmatrix} 2 & 4 \ 3 & 2 \end{bmatrix} \begin{bmatrix} 1 & 3 \ -2 & 5 \end{bmatrix}$$AB = \begin{bmatrix} (2 	imes 1) + (4 	imes -2) & (2 	imes 3) + (4 	imes 5) \ (3 	imes 1) + (2 	imes -2) & (3 	imes 3) + (2 	imes 5) \end{bmatrix}$$AB = \begin{bmatrix} 2 - 8 & 6 + 20 \ 3 - 4 & 9 + 10 \end{bmatrix}$$AB = \begin{bmatrix} -6 & 26 \ -1 & 19 \end{bmatrix}$

Let $A = \begin{bmatrix} 2 & 4 \\ 3 & 2 \end{bmatrix}$,$B = \begin{bmatrix} 1 & 3 \\ -2 & 5 \end{bmatrix}$,and $C = \begin{bmatrix} -2 & 5 \\ 3 & 4 \end{bmatrix}$. Find $AB$.

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