Let $A = \left\{ {{x_1},{x_2},{x_3},.....,{x_7}} \right\}$ and $B = \left\{ {{y_1},{y_2},{y_3}} \right\}$ be two sets containing seven and three distinct elements respectively. Then the total number of functions $f:A \to B$ which are onto, if there exist exactly three elements $x$ in $A$ such that $f(x) = {y_2}$ , is equal to

  • A

    $14{(^7}{C_2})$

  • B

    $16{(^7}{C_3})$

  • C

    $12{(^7}{C_2})$

  • D

    $14{(^7}{C_3})$

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