Kolbe electrolysis of potassium succinate giv | vedclass

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(C) Kolbe electrolysis of potassium succinate involves the decarboxylation of the salt of a dicarboxylic acid.Potassium succinate is $K_2C_4H_4O_4$ (o

Vedclass · Accepted Answer

$C_2H_4, \, KOH$ and $H_2$

Vedclass · Answer

(C) Kolbe electrolysis of potassium succinate involves the decarboxylation of the salt of a dicarboxylic acid.Potassium succinate is $K_2C_4H_4O_4$ (or $KOOC-CH_2-CH_2-COOK$).The reaction is: $K_2C_4H_4O_4 + 2H_2O \xrightarrow{	ext{electrolysis}} C_2H_4 + 2CO_2 + 2KOH + H_2$.Thus,the products are ethene $(C_2H_4)$,carbon dioxide $(CO_2)$,potassium hydroxide $(KOH)$,and hydrogen gas $(H_2)$.

Kolbe electrolysis of potassium succinate gives $CO_2$ and

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