Keto-enol tautomerism is found in

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(D) Keto-enol tautomerism requires the presence of at least one $\alpha$-hydrogen atom adjacent to a carbonyl group $(C=O)$.$1. \ C_6H_5-CO-CH_3$ (Ace

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$Both \ (b) \ and \ (c)$

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(D) Keto-enol tautomerism requires the presence of at least one $\alpha$-hydrogen atom adjacent to a carbonyl group $(C=O)$.$1. \ C_6H_5-CO-CH_3$ (Acetophenone) has three $\alpha$-hydrogens on the methyl group,allowing it to form an enol: $C_6H_5-C(OH)=CH_2$.$2. \ C_6H_5-CO-CH_2-CO-CH_3$ ($1$-phenylbutane$-1,3-$dione) has active methylene hydrogens between two carbonyl groups,which are highly acidic and readily undergo tautomerism to form an enol: $C_6H_5-CO-CH=C(OH)-CH_3$.$3. \ C_6H_5-CHO$ (Benzaldehyde) has no $\alpha$-hydrogen atom,so it cannot exhibit keto-enol tautomerism.Therefore,both $(b)$ and $(c)$ exhibit keto-enol tautomerism.

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