Is $0.2$ a root of the equation $x^{2}-0.4=0$? Justify.
(B) To determine if $0.2$ is a root of the equation $x^{2}-0.4=0$,we substitute $x = 0.2$ into the equation.
Substituting $x = 0.2$ into the left-hand side $(LHS)$ gives:
$(0.2)^{2} - 0.4 = 0.04 - 0.4 = -0.36$.
Since the result is $-0.36$ and not $0$,the value $0.2$ does not satisfy the equation.
Therefore,$0.2$ is not a root of the equation $x^{2}-0.4=0$.
Substituting $x = 0.2$ into the left-hand side $(LHS)$ gives:
$(0.2)^{2} - 0.4 = 0.04 - 0.4 = -0.36$.
Since the result is $-0.36$ and not $0$,the value $0.2$ does not satisfy the equation.
Therefore,$0.2$ is not a root of the equation $x^{2}-0.4=0$.
Explore More
Similar Questions
Divide $29$ into two parts such that the sum of their squares is $425$.
Difficult
View SolutionObtain the roots of the following equation using the method of 'completing the square': $m^{2} - 18m + 81 = 0$
Medium
View SolutionFind the discriminant of the following quadratic equation and hence determine the nature of the roots of the equation: $x^{2} + x - 3 = 0$
Easy
View SolutionExamine whether the following equation is quadratic or not: $\frac{x-2}{x+2} - \frac{x+2}{x-2} = \frac{3}{7}$
Easy
View SolutionIf the roots of the equation $6x^2 - 13x + m = 0$ are reciprocal of each other,then $m = $ ...........
Easy
View SolutionVedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo